2x^2-15x-638=0

Solution for 2x^2-15x-638=0 equation:

2x^2-15x-638=0

a = 2; b = -15; c = -638;
Δ = b2-4ac
Δ = -152-4·2·(-638)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5329}=73$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-73}{2*2}=\frac{-58}{4}
=-14+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+73}{2*2}=\frac{88}{4}
=22
$